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@mod @mod_forum
Feature: Forum discussions can be split
In order to manage forum discussions in my course
As a Teacher
I need to be able to split threads to keep them on topic.
Background:
Given the following "users" exist:
| username | firstname | lastname | email |
| teacher1 | Teacher | 1 | teacher1@example.com |
| student1 | Student | 1 | student1@example.com |
| student2 | Student | 2 | student2@example.com |
And the following "courses" exist:
| fullname | shortname | category |
| Science 101 | C1 | 0 |
And the following "course enrolments" exist:
| user | course | role |
| teacher1 | C1 | editingteacher |
| student1 | C1 | student |
| student2 | C1 | student |
And the following "activities" exist:
| activity | name | course | idnumber | type |
| forum | Study discussions | C1 | forump1 | general |
And the following "mod_forum > discussions" exist:
| forum | course | user | name | message |
| forump1 | C1 | teacher1 | Photosynthesis discussion | Lets discuss our learning about Photosynthesis this week in this thread. |
And the following "mod_forum > posts" exist:
| user | parentsubject | subject | message |
| student1 | Photosynthesis discussion | Mass number | Can anyone tell me which number is the mass number in the periodic table? |
| student2 | Mass number | | I would also like to know this |
Scenario: Split a forum discussion
Given I am on the "Study discussions" "forum activity" page logged in as teacher1
And I follow "Photosynthesis discussion"
When I follow "Split"
And I set the following fields to these values:
| Discussion name | Mass number in periodic table |
And I press "Split"
Then I should see "Mass number in periodic table"
And I follow "Study discussions"
And I should see "Teacher 1" in the "Photosynthesis" "table_row"
# Confirm that the last post author has been updated.
And I should not see "Student 2" in the "Photosynthesis" "table_row"
# Confirm that the current author has been shown for the new split discussion.
And I should see "Student 1" in the "Mass number in periodic table" "table_row"